0=-16x^2+70x+8

Solution for 0=-16x^2+70x+8 equation:

0=-16x^2+70x+8

We move all terms to the left:

0-(-16x^2+70x+8)=0

We add all the numbers together, and all the variables

-(-16x^2+70x+8)=0

We get rid of parentheses

16x^2-70x-8=0

a = 16; b = -70; c = -8;
Δ = b2-4ac
Δ = -702-4·16·(-8)
Δ = 5412
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5412}=\sqrt{4*1353}=\sqrt{4}*\sqrt{1353}=2\sqrt{1353}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{1353}}{2*16}=\frac{70-2\sqrt{1353}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{1353}}{2*16}=\frac{70+2\sqrt{1353}}{32}
$